How do you factor $- 8 x^{2} + 32$ $-8x^2 +32$ ?

Question

5726 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-15T01:09:52

$- 8 x^{2} + 32 = 8 [4 - x^{2}] = - 8 [x^{2} - 4] = 8 [(x - 2) \cdot (x + 2)]$ $-8x^2+32=8[4-x^2]=-8[x^2-4]=8[(x-2)*(x+2)]$

show below

$- 8 x^{2} + 32 = 8 [4 - x^{2}] = - 8 [x^{2} - 4] = 8 [(x - 2) \cdot (x + 2)]$ $-8x^2+32=8[4-x^2]=-8[x^2-4]=8[(x-2)*(x+2)]$

How do you factor −8x2+32 -8x^2 +32?