How do you factor x38y3?

1 Answer
Apr 9, 2015

We can write this expression as x3(2y)3

The formula for factorizing the Difference of two Cubes is:
a3b3=(ab)(a2+ab+b2)

In x3(2y)3,
a=x
b=2y

x3(2y)3
=(x2y)(x2+(x2y)+(2y)2)
=(x2y)(x2+2xy+4y2)

As we cannot factorize any of the factors further, we can say that we have factorised x38y3 completely.