How do you use the special product of a sum and difference to multiply $(3x^2+2)(3x^2-2)$ ?

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Answer 1 · 2014-12-11T06:18:30

Remeber

$(a+b)(a-b)=a^2-b^2$

By setting ${(a=3x^2),(b=2):}$ , we have

$(3x^2+2)(3x^2-2)=(3x^2)^2-(2)^2=9x^4-4$

I hope that this was helpful.

How do you use the special product of a sum and difference to multiply (3x^2+2)(3x^2-2)(3x^2+2)(3x^2-2)?