How do you factor $8x² − 72$ ?

Question

4556 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-02T11:14:34

$8(x^2-3^2)=8(x+3(x-3)$

Answer 2 · 2016-04-02T11:16:32

$8(x+3)(x-3)$

First, we can facter $8$ out of the expression as the two terms are multiples of $8$ .

$8x^2-72=8(x^2-9)$

Now in the brackets we see that we have the difference of 2 squares, ( $x^2 = (x)^2$ and $9 = 3^2$ ) so we can further factorise to:

$8(x+3)(x-3)$

And we're done.

How do you factor 8x² − 72 8x² − 72 ?