How do you factor 36x^2-4936x2−49? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer Meave60 Jun 28, 2015 Use the difference of squares equation: (a^2-b^2)=(a+b)(a-b)(a2−b2)=(a+b)(a−b). Identify aa and bb, and substitute the values into the equation. Explanation: 36x^2-4936x2−49 is in the form of the difference of squares: (a^2-b^2)=(a+b)(a-b)(a2−b2)=(a+b)(a−b) a=6xa=6x b=7b=7 36x^2-49=(6x+7)(6x+7)36x2−49=(6x+7)(6x+7) Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying (x+10)^2(x+10)2? How do you use the special product for squaring binomials to multiply (1/4t+2 )^2(14t+2)2? How do you use the special product of a sum and difference to multiply (3x^2+2)(3x^2-2)(3x2+2)(3x2−2)? How do you evaluate 56^2562 using special products? How do you multiply (3x-2y)^2(3x−2y)2? How do you factor -8x^2 +32−8x2+32? How do you factor x^3-8y^3x3−8y3? How do you factor x^3 - 1x3−1? See all questions in Special Products of Polynomials Impact of this question 12663 views around the world You can reuse this answer Creative Commons License