How do you factor $16x^2=56x$ ?

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Answer 1 · 2015-07-01T22:43:02

$8x(2x-7)=0$

We will move the right-hand side to the left-hand side :

$16x^2 = 56x$ <=> $16x^2 - 56x = 0$

After that, we have to find the common factor inside the subtraction :

$16x^2 = color(red)(2*2*2)*2*x*color(green)x$ and $56x = color(red)(2*2*2)*7*color(green)x$

Then the common factor of $16x^2$ and $56x$ is $color(red)(2*2*2)*color(green)x = 8x$ and so : $16x^2 = 8x * 2x$ and $56x = 8x *7$

Therefore, the factorization of $16x^2-56x=0$ is :
$8x*2x - 8x*7 = 0$ <=> $8x.(2x-7)=0$

And now you can solve this equation with the property of multiplication!

How do you factor 16x^2=56x16x^2=56x?