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How do you factor #13(x^6+ 1)^4#?

1 Answer

Jan 24, 2018

#13 (x^2+1)^4 (x^4 - x^2 + 1)^4#

Explanation:

#a^3 + b^3 = (a+b)(a^2-ab+b^2)#
#=> x^6 + 1 = (x^2 + 1)(x^4 - x^2 + 1)#
#=> 13(x^6+1)^4 = 13 (x^2+1)^4 (x^4 - x^2 + 1)^4#

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