How do you call a spectrum with no C-H splitting?

1 Answer
Aug 8, 2015

A 13C NMR spectrum with no C-H coupling is called a proton decoupled spectrum.

Explanation:

Proton-Coupled Spectra

The 13C signals are split by the H atoms attached to them.

These splittings are much larger than in 1H spectra (JC-H=100 – 250 Hz; JH-H=0 – 15 Hz).

The spectra are more complicated and harder to interpret if the signals are close together.

The figure below shows the proton-coupled 13C NMR spectrum for ethyl phenylacetate.

chem.sci.ubu.ac.th
(from chem.sci.ubu.ac.th)

The methyl signal is a quartet, the methylene signals are triplets, and the aromatic signals are doublets.

Proton-Decoupled Spectra

In a "normal" 13C spectrum, these couplings are "removed" by applying a continuous second radio frequency that excites all the H nuclei at once.

They "flip" between energy states so fast that the C atoms "see" only an average unperturbed field, and the coupling is removed.

This means that each C signal becomes a single line.

The spectrum of ethyl phenylacetate reduces to a single peak for each of the eight types of carbon atom.

chem.sci.ubu.ac.th
(from chem.sci.ubu.ac.th)

The advantage of decoupling is that it gives a cleaner spectrum, as carbon signals are often close for complex molecules, and fewer peaks mean less overlap.