A circle's center is at (9 ,7 ) and it passes through (6 ,2 ). What is the length of an arc covering (5 pi ) /6 radians on the circle?

1 Answer
bp
Nov 2, 2016

First of all the radius of the circle would be the distance between the center at (9,7) and the point (6,2) on the circle. This would be sqrt((9-6)^2 + (7-2)^2) = sqrt34 cms

Arc length formula is s= rtheta where angle (theta) is measured in radians. In the present case theta = (5pi)/6 , hence arc length would besqrt34 * (5pi)/6 = 15.26 cms

Related questions
See all questions in Circle Arcs and Sectors
Impact of this question
1337 views around the world
You can reuse this answer
Creative Commons License