A circle's center is at $(9, 6)$ $(9 ,6 )$ and it passes through $(6, 2)$ $(6 ,2 )$ . What is the length of an arc covering $\frac{5 π}{6}$ $(5 pi ) /6$ radians on the circle?

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A circle's center is at $(9, 6)$ $(9 ,6 )$ and it passes through $(6, 2)$ $(6 ,2 )$ . What is the length of an arc covering $\frac{5 π}{6}$ $(5 pi ) /6$ radians on the circle?

1 Answer

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Answer 1 · 2016-03-23T15:13:30

$= 13 u n i t$ $=13 unit$

Explanation:

Radius of the circle $R = \sqrt{{(9 - 6)}^{2} + {(6 - 2)}^{2}} = \sqrt{25} = 5$ $R= sqrt((9-6)^2+(6-2)^2)=sqrt25=5$
The arc length = $R \times 5 \times \frac{π}{6} = 5 \times 5 \times \frac{π}{6} = 13 u n i t$ $Rxx5xxpi/6=5xx5xxpi/6=13 unit$

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A circle's center is at $(9, 6)$ $(9 ,6 )$ and it passes through $(6, 2)$ $(6 ,2 )$ . What is the length of an arc covering $\frac{5 π}{6}$ $(5 pi ) /6$ radians on the circle?

1 Answer

Explanation:

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1 Answer

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A circle's center is at $(9, 6)$ $(9 ,6 )$ and it passes through $(6, 2)$ $(6 ,2 )$ . What is the length of an arc covering $\frac{5 π}{6}$ $(5 pi ) /6$ radians on the circle?