A circle's center is at $(9 ,4 )$ and it passes through $(1 ,6 )$ . What is the length of an arc covering $(2pi ) /3$ radians on the circle?

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Answer 1 · 2016-03-11T06:27:38

$=17.2$ unit

radius of the circle $r=sqrt((9-1)^2+(4-6)^2)=sqrt68$
angle subtended buy arc at center $(theta=2pi/3)$

Arc langth $S=rxxtheta=sqrt68xx2xxpi/3=17.2$

A circle's center is at (9 ,4 )(9 ,4 ) and it passes through (1 ,6 )(1 ,6 ). What is the length of an arc covering (2pi ) /3 (2pi ) /3 radians on the circle?