A circle's center is at $(5, 5)$ $(5 ,5 )$ and it passes through $(2, 7)$ $(2 ,7 )$ . What is the length of an arc covering $\frac{7 π}{8}$ $(7pi ) /8$ radians on the circle?

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Answer 1 · 2016-02-04T22:25:18

$≅ 9.911$ $~= 9.911$

$r = \sqrt{{(5 - 2)}^{2} + {(5 - 7)}^{2}} = \sqrt{9 + 4} = \sqrt{13}$ $r=sqrt((5-2)^2+(5-7)^2)=sqrt(9+4)=sqrt(13)$

so length of arc is:

$\sqrt{13} \times \frac{7 π}{8} ≅ 9.911$ $sqrt(13)xx(7pi)/8 ~= 9.911$

A circle's center is at (5,5)(5 ,5 ) and it passes through (2,7)(2 ,7 ). What is the length of an arc covering 7π8(7pi ) /8 radians on the circle?