A circle's center is at $(4 ,6 )$ and it passes through $(2 ,4 )$ . What is the length of an arc covering $(pi ) /3$ radians on the circle?

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Answer 1 · 2016-03-07T06:44:35

$s=rtheta=2sqrt2*pi/3=2.96192 " "$ units

The length of arc is given $s=r theta$ where $r=$ radius, $theta=$ central angle in radian

compute $r=sqrt((4-2)^2+(6-4)^2)=2sqrt2$

$theta=pi/3$

$s=rtheta=2sqrt2*pi/3=2.96192 " "$ units

God bless...I hope the explanation is useful.

A circle's center is at (4 ,6 )(4 ,6 ) and it passes through (2 ,4 )(2 ,4 ). What is the length of an arc covering (pi ) /3 (pi ) /3 radians on the circle?