A circle's center is at #(3 ,3 )# and it passes through #(4 ,5 )#. What is the length of an arc covering #( pi ) /6 # radians on the circle?

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Answer 1 · 2016-11-05T09:42:14

#s=pisqrt10/6#

the arc length of a circle is

#s=rtheta#

where #r# is the radius, and #theta# the angle in radians subtended at the centre.

radius #r=sqrt((4-3)^2+(5-2)^2)#

#r=sqrt(1^2+3^2)=sqrt10#

#:.s=rtheta=sqrt10xxpi/6#

#s=pisqrt10/6#