A circle has a chord that goes from pi/4 π4 to pi/2 π2 radians on the circle. If the area of the circle is 9 pi 9π, what is the length of the chord?

1 Answer
Jul 18, 2017

The length of the chord is =2.3u=2.3u

Explanation:

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The angle subtented at the center of the circle is

theta=1/2pi-1/4pi=1/4piθ=12π14π=14π

The area of the circle is

A=pir^2A=πr2

So, the radius is

r=sqrt(A/pi)=sqrt(9pi/pi)=3r=Aπ=9ππ=3

The length of the chord is

AB=2*AC=2*r*sin(theta/2)AB=2AC=2rsin(θ2)

=2*3*sin(1/8pi)=23sin(18π)

=2.3=2.3