A circle has a chord that goes from $\frac{π}{3}$ $pi/3$ to $\frac{π}{2}$ $pi/2$ radians on the circle. If the area of the circle is $49 π$ $49 pi$ , what is the length of the chord?

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A circle has a chord that goes from $\frac{π}{3}$ $pi/3$ to $\frac{π}{2}$ $pi/2$ radians on the circle. If the area of the circle is $49 π$ $49 pi$ , what is the length of the chord?

1 Answer

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Answer 1 · 2016-04-16T11:59:13

3.7 units

Explanation:

The area of a circle is given as $π r^{2}$ $pir^2$ . So for this case the radius is 7.

The angle that the chord holds at the centre is $\frac{π}{2} - \frac{π}{3} = \frac{π}{6}$ $pi/2-pi/3 = pi/6$ So the length of the chord is $2 \cdot 7 sin (\frac{π}{12}) \approx 3.7$ $2*7sin(pi/12)~~3.7$

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A circle has a chord that goes from $\frac{π}{3}$ $pi/3$ to $\frac{π}{2}$ $pi/2$ radians on the circle. If the area of the circle is $49 π$ $49 pi$ , what is the length of the chord?

1 Answer

Explanation:

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A circle has a chord that goes from $\frac{π}{3}$ $pi/3$ to $\frac{π}{2}$ $pi/2$ radians on the circle. If the area of the circle is $49 π$ $49 pi$ , what is the length of the chord?