A circle has a chord that goes from ( pi)/3 to (5 pi) / 12 radians on the circle. If the area of the circle is 16 pi , what is the length of the chord?

1 Answer
Mar 1, 2017

length of chord ~~1.04

Explanation:

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As area of a circle is given by pir^2 and it is 16pi, we have r=sqrt16=4.

As shown in the figure, the angle Theta subtended at the centre by the chord is (5pi)/12-pi/3=pi/12

=> AM=rsin(Theta/2)
=> length of chord =AB=2AM=2rsin(Theta/2)
=2*4*sin(pi/24)=1.04 (2dp)