A circle has a chord that goes from ( pi)/2 π2 to (3 pi) / 4 3π4 radians on the circle. If the area of the circle is 196 pi 196π, what is the length of the chord?
1 Answer
Aug 17, 2017
Explanation:
• " the area of a circle "=pir^2∙ the area of a circle =πr2
rArrpir^2=196pi⇒πr2=196π
rArrr^2=(196cancel(pi))/cancel(pi)=196
rArrr=sqrt196=14
"the angle subtended at the centre of the circle by the"
"chord is"
(3pi)/4-pi/2=(3pi)/4-(2pi)/4=pi/4
"we now have a triangle made up of the 2 radii and the"
"chord "
"to find length of chord use the "color(blue)"cosine rule"
•color(white)(x)c^2=a^2+b^2-2abcosC
"where "a=b=14" and "angleC=pi/4
c^2=14^2+14^2-(2xx14xx14xxcos(pi/4))
color(white)(c^2)~~ 114.814
rArrc=sqrt114.814~~ 10.72" to 2 dec. places"
rArr"length of chord "~~ 10.72