A circle has a chord that goes from ( pi)/2 π2 to (3 pi) / 4 3π4 radians on the circle. If the area of the circle is 196 pi 196π, what is the length of the chord?

1 Answer
Aug 17, 2017

~~ 10.7210.72

Explanation:

• " the area of a circle "=pir^2 the area of a circle =πr2

rArrpir^2=196piπr2=196π

rArrr^2=(196cancel(pi))/cancel(pi)=196

rArrr=sqrt196=14

"the angle subtended at the centre of the circle by the"
"chord is"

(3pi)/4-pi/2=(3pi)/4-(2pi)/4=pi/4

"we now have a triangle made up of the 2 radii and the"
"chord "

"to find length of chord use the "color(blue)"cosine rule"

•color(white)(x)c^2=a^2+b^2-2abcosC

"where "a=b=14" and "angleC=pi/4

c^2=14^2+14^2-(2xx14xx14xxcos(pi/4))

color(white)(c^2)~~ 114.814

rArrc=sqrt114.814~~ 10.72" to 2 dec. places"

rArr"length of chord "~~ 10.72