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Answer 1 · 2017-06-18T13:26:22

You must use 46 mL of the concentrated #"HCl"#.

You can use the dilution formula

#color(blue)(bar(ul(|color(white)(a/a)c_1V_1 = c_2V_2color(white)(a/a)|)))" "#

where #c_1# and #c_2# are the concentrations and #V_1# and #V_2# are the volumes.

You can rearrange this formula to get

#V_1 = V_2 × c_2/c_1#

Your data are:

#c_1 = "10.0 mol/L"; V_1 = "?"#
#c_2 = "2.0 mol/L"; color(white)(ll)V_2 = "231 mL"#

#V_1 = "231 mL" × (2.0 color(red)(cancel(color(black)("mol/L"))))/(10.0 color(red)(cancel(color(black)("mol/L")))) = "46 mL"#