Question #5e370

1 Answer
Douglas K.
Mar 26, 2017

The Standard Cartesian Form for the equation of a circle is:
(x−h)2+(y−k)2=r2 [1]
Where (x,y) is any point on the circle, (h,k) is the center, and r is the radius.

Explanation:

Given that the center is (0,0) we substitute this into equation [1] to obtain equation [2]:

(x−0)2+(y−0)2=r2 [2]

Substitute the point (12−5) into equation [2] and solve for r:

(12−0)2+(−5−0)2=r2

169=r2

r=13

Substitute 13 for r in equation [2]:

(x−0)2+(y−0)2=132 [3]

Equation [3] is the equation of the specified circle.

Here is its graph:

graph{(x-0)^2+(y-0)^2=13^2 [-30, 30, -15, 15]}

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