Question #64b2f

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Answer 1 · 2016-03-23T15:08:42

$x=1.3083+-0.6324i$

To solve for $x$ in the quadratic equation

$y=-0.7428x^2+1.9437x-1.569$

Use the quadratic formula, which solves for $x$ in the quadratic equation

$y=ax^2+bx+c$

where

$x=(-b+-sqrt(b^2-4ac))/(2a)$

In the given quadratic, we see that

${(a=-0.7428),(b=1.9437),(c=-1.569):}$

Thus,

$x=(-1.9437+-sqrt(1.9437^2-4(-0.7428)(-1.569)))/(2(-0.7428))$

$x=(-1.9437+-sqrt(-0.8838))/(-1.4856)$

Bring the negative out as $i$ . Take the square root of $0.8838$ .

$x=(-1.9437)/(-1.4865)+-0.9401/(-1.4856)i$

$x=1.3083+-0.6324i$