Question #f0d1e

1 Answer
Roella W.
Mar 17, 2016

This is an ellipse with centre at #(2,3)# and foci at #sqrt(5)# either side of the centre.

Explanation:

This is the equation of an ellipse, which you can recognise by the fact the both the #x^2# and the #y^2# terms are positive. By using the completing the squares method the equation can be rearranged into a form that will give the key dimensions and points needed to draw the graph.
#x^2 -4x +y^2 - 6y +8 = 0#
#(x-2)^2 -4 +(y-3)^2 - 9 +8 = 0#
#(x-2)^2 +(y-3)^2 =5#

#(x-2)^2/5 + (y-3)^2/5 = 1#

This is an ellipse with centre at #(2,3)# and foci at #sqrt(5)# either side of the centre.

Related questions
See all questions in Circle Arcs and Sectors
Impact of this question
1580 views around the world
You can reuse this answer
Creative Commons License