Ratio Test for Convergence of an Infinite Series

Key Questions

  • It is not always clear-cut, but if a series contains exponential functions or/and factorials, then Ratio Test is probably a good way to go.


    I hope that this was helpful.

  • By Ratio Test, the posted series converges absolutely.

    By Ratio Test:

    #lim_{n to infty}|a_{n+1}/a_n|=lim_{n to infty}|{(-10)^{n+1}}/{4^{2n+3}(n+2)}cdot{4^{2n+1}(n+1)}/{(-10)^n}|#

    By canceling out common factors:

    #=lim_{n to infty}|{-10(n+1)}/{4^2(n+2)}|#

    since #|{-10}/4^2|=5/8#, we have:

    #=5/8lim_{n to infty}(n+1)/(n+2)#

    by dividing the numerator and the denominator by #n#,

    #=5/8 lim_{n to infty}{1+1/n}/{1+2/n}=5/8cdot 1=5/8<1#

    Hence, #sum_{n=1}^{infty}{(-10)^n}/{4^{2n+1}(n+1)}# is absolutely convergent.

Questions