How do you use the ratio test to test the convergence of the series ∑ (8^n)/(n!)8nn! from n=1 to infinity?

1 Answer
Oct 15, 2015

The series would converge.

Explanation:

To test the convergence apply the ratio test which means to find

lim_ (n->oo) (a_(n+1) /a_n). If limit is <1, the series would converge. In the present case this limit is,

= lim_ (n->oo) (8^(n+1))/((n+1)!) * (n!)/8^n

= lim_ (n->oo) 8/(n+1) =0.Hence the series would converge.