How do you use the ratio test to test the convergence of the series $∑ (3/4)^n$ from n=1 to infinity?

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Answer 1 · 2016-12-12T14:21:25

The series is convergent and:

$sum_(n=1)^(+oo) (3/4)^n = 3$

The ratio to test is:

$r= a_(n+1)/a_n= frac ((3/4)^(n+1)) ((3/4)^n) =3/4$

As $r<1$ the series is convergent.

We can note that this is a particular case of the geometric series:

$sum_(n=0)^(+oo) x^n = 1/(1-x)$ for $|x|<1$ .

So that we can also calculate the sum:

$sum_(n=1)^(+oo) (3/4)^n = -1 + sum_(n=0)^(+oo) (3/4)^n = -1+1/(1-3/4) = -1 + 1/(1/4)=-1+4=3$

How do you use the ratio test to test the convergence of the series ∑ (3/4)^n∑ (3/4)^n from n=1 to infinity?