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How do you solve by completing the square for #x^2-7x+12=0#?

1 Answer

Nghi N. · Alan P.

May 27, 2015

#f(x) = x^2 - 7x + 49/4 - 49/4 + 12 = 0#

#f(x) = (x - 7/2)^2 - 49/4 + 48/4 = 0#

#(x - 7/2) = +- 1/2#

#x = 7/2 +- 1/2#

#x = 8/2 = 4#
or
#x=6/2 =3#

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