How do you solve for t in 2/7(t+2/3)=1/5(t-2/3)27(t+23)=15(t−23)?

1 Answer
Manish Bhardwaj · Tanish J.
Sep 28, 2014

We can solve the question using the distributive property.

2/7 ( t+ 2/3) = 1/5 (t-2/3)27(t+23)=15(t−23)

Multiplying , we get

(2/7) * t + (2/7)*(2/3) = (1/5 ) * t - (1/5) * (2/3)(27)⋅t+(27)⋅(23)=(15)⋅t−(15)⋅(23)

(2t) /7 + 4/21 = t/5 - 2/152t7+421=t5−215

Taking the like terms to one side of the equation;

(2t)/7 -t/5 = -2/15 -4/212t7−t5=−215−421

Taking LCM,

(10t - 7t ) / 35 = ((-2 * 7 ) + (-4 * 5)) / 10510t−7t35=(−2⋅7)+(−4⋅5)105

(3t) / 35 = -34 /1053t35=−34105

3t = (-34*35 ) / 1053t=−34⋅35105

3t = (-34 * 1 ) / 33t=−34⋅13

3t = -34 / 33t=−343

t = -34 /9 = -3.7 7 or -4t=−349=−3.77or−4

Related questions
See all questions in Equations with Variables on Both Sides
Impact of this question
8484 views around the world
You can reuse this answer
Creative Commons License