What volume of water would be added to 16.5 mL of a 0.0813 M solution of sodium borate in order to get a 0.0200 M solution?

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Answer 1 · 2014-05-05T11:19:57

To solve this we'll need to apply the equation

#M_1V_1 = M_2V_2#

#V_1 = 16.5ml#
#V_2 = ?#
#M_1 = 0.0813#
#M_2 = 0.200#

Solve the equation for V2
#V_2# = #(M_1V_1)/M_2#

#V_2# = #(0.0813M . 16.5ml) / (0.0200M# = #67.1ml#

Please note the question asks you to find the volume that must be added. You'll need to subtract 16.5mL from 67.1 to find the answer of
50.6mL.

Here is a video which discusses how to perform dilution calculations.