What volume of 5.0 M $N a O H$ $NaOH$ is required to make 100 mL 2.0 M $N a O H$ $NaOH$ ?

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What volume of 5.0 M $N a O H$ $NaOH$ is required to make 100 mL 2.0 M $N a O H$ $NaOH$ ?

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Answer 1 · 2016-05-02T06:10:42

$40 \cdot m L$ $40*mL$ of $5.0 \cdot m o l \cdot L^{- 1}$ $5.0*mol*L^-1$ sodium hydoxide are required.

Explanation:

The $concentration \times volume$ $"concentration"xx"volume"$ gives answer in amount of substance.

Thus $C_{1} V_{1} = C_{2} V_{2}$ $C_1V_1=C_2V_2$ , where $C_{1}, V_{1}$ $C_1, V_1$ are the initial concentrations, volume etc.

We need to find $V_{1}$ $V_1$ $=$ $=$ $\frac{[C_{1}] [V_{2}]}{[C_{2}]}$ $([C_1][V_2])/([C_2])$

$= \frac{2.0 \cdot m o l \cdot L^{- 1} \times 0.100 \cdot L}{5.0 \cdot m o l \cdot L^{- 1}}$ $=(2.0*mol*L^-1xx0.100*L)/(5.0*mol*L^-1)$ $=$ $=$ $? ? \cdot L = ? ? \cdot m L$ $??*L=??*mL$

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What volume of 5.0 M $N a O H$ $NaOH$ is required to make 100 mL 2.0 M $N a O H$ $NaOH$ ?

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What volume of 5.0 M $N a O H$ $NaOH$ is required to make 100 mL 2.0 M $N a O H$ $NaOH$ ?