What volume of 5.0 M $NaOH$ is required to make 100 mL 2.0 M $NaOH$ ?

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Answer 1 · 2016-05-02T06:10:42

$40*mL$ of $5.0*mol*L^-1$ sodium hydoxide are required.

The $"concentration"xx"volume"$ gives answer in amount of substance.

Thus $C_1V_1=C_2V_2$ , where $C_1, V_1$ are the initial concentrations, volume etc.

We need to find $V_1$ $=$ $([C_1][V_2])/([C_2])$

$=(2.0*mol*L^-1xx0.100*L)/(5.0*mol*L^-1)$ $=$ $??*L=??*mL$

What volume of 5.0 M NaOHNaOH is required to make 100 mL 2.0 M NaOHNaOH?