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What volume of 5.0 M #NaOH# is required to make 100 mL 2.0 M #NaOH#?

1 Answer

May 2, 2016

#40*mL# of #5.0*mol*L^-1# sodium hydoxide are required.

Explanation:

The #"concentration"xx"volume"# gives answer in amount of substance.

Thus #C_1V_1=C_2V_2#, where #C_1, V_1# are the initial concentrations, volume etc.

We need to find #V_1# #=# #([C_1][V_2])/([C_2])#

#=(2.0*mol*L^-1xx0.100*L)/(5.0*mol*L^-1)# #=# #??*L=??*mL#

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