What is the equation of the circle with a center at #(6 ,-1 )# and a radius of #1 #?
1 Answer
Jan 26, 2016
Explanation:
The standard form of a circle with a center at
#(x-h)^2+(y-k)^2=r^2#
Since the center is
#{(h=6),(k=-1),(r=1):}#
Thus, the equation of the circle is
#(x-6)^2+(y-(-1))^2=1^2#
This simplifies to be
#(x-6)^2+(y+1)^2=1#