What is the equation of the circle with a center at #(6 ,-1 )# and a radius of #1 #?

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Answer 1 · 2016-01-26T22:57:10

#(x-6)^2+(y+1)^2=1#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(6,-1)# and the radius is #1#, we know that

#{(h=6),(k=-1),(r=1):}#

Thus, the equation of the circle is

#(x-6)^2+(y-(-1))^2=1^2#

This simplifies to be

#(x-6)^2+(y+1)^2=1#