What is the equation of the circle with a center at $(5, 7)$ $(5 ,7 )$ and a radius of $1$ $1$ ?

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What is the equation of the circle with a center at $(5, 7)$ $(5 ,7 )$ and a radius of $1$ $1$ ?

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Answer 1 · 2016-03-25T16:09:56

${(x - 5)}^{2} + {(y - 7)}^{2} = 1$ $(x - 5 )^2 +(y - 7 )^2 = 1$

Explanation:

The standard form of the equation of a circle is:

${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x - a )^2 + (y - b )^2 = r^2$

where (a , b ) are the coords of centre and r , the radius

here a = 5 , b = 7 and r = 1

substitute these values into the equation of circle

$\Rightarrow {(x - 5)}^{2} + {(y - 7)}^{2} = 1$ $rArr (x - 5 )^2 + (y - 7 )^2 = 1$

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