What is the equation of the circle with a center at (4 ,-7 ) and a radius of 8 ?
1 Answer
Jan 26, 2016
Explanation:
The standard form of a circle with a center at
(x-h)^2+(y-k)^2=r^2
Since the center is
{(h=4),(k=-7),(r=8):}
Thus, the equation of the circle is
(x-4)^2+(y-(-7))^2=8^2
This simplifies to be
(x-4)^2+(y+7)^2=64