What is the equation of the circle with a center at (4 ,-7 )(4,7) and a radius of 8 8?

1 Answer
Jan 26, 2016

(x-4)^2+(y+7)^2=64(x4)2+(y+7)2=64

Explanation:

The standard form of a circle with a center at (h,k)(h,k) and a radius rr is

(x-h)^2+(y-k)^2=r^2(xh)2+(yk)2=r2

Since the center is (4,-7)(4,7) and the radius is 88, we know that

{(h=4),(k=-7),(r=8):}

Thus, the equation of the circle is

(x-4)^2+(y-(-7))^2=8^2

This simplifies to be

(x-4)^2+(y+7)^2=64