What is the equation of the circle with a center at #(4 ,-7 )# and a radius of #8 #?

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Answer 1 · 2016-01-26T22:45:53

#(x-4)^2+(y+7)^2=64#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(4,-7)# and the radius is #8#, we know that

#{(h=4),(k=-7),(r=8):}#

Thus, the equation of the circle is

#(x-4)^2+(y-(-7))^2=8^2#

This simplifies to be

#(x-4)^2+(y+7)^2=64#