What is the equation of the circle with a center at $(-4 ,6 )$ and a radius of $3$ ?

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Answer 1 · 2016-07-25T17:59:38

$x^2+y^2+8x-12y+43=0$

Eqn. of a circle with centre $(h,k) and radius=r$ is given by,

$(x-h)^2+(y-k)^2=r^2$

In our case, the eqn. is, $(x+4)^2+(y-6)^2=3^2$ , i.e.,

$x^2+y^2+8x-12y+43=0$

What is the equation of the circle with a center at (-4 ,6 )(-4 ,6 ) and a radius of 3 3 ?