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Answer 1 · 2016-07-25T17:59:38

#x^2+y^2+8x-12y+43=0#

Eqn. of a circle with centre #(h,k) and radius=r# is given by,

#(x-h)^2+(y-k)^2=r^2#

In our case, the eqn. is, #(x+4)^2+(y-6)^2=3^2#, i.e.,

#x^2+y^2+8x-12y+43=0#