What is the equation of the circle with a center at $(4 ,-3 )$ and a radius of $5$ ?

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Answer 1 · 2016-01-26T22:21:20

$(x-4)^2+(y+3)^2=25$

The standard form of a circle with a center at $(h,k)$ and a radius $r$ is

$(x-h)^2+(y-k)^2=r^2$

Since the center is $(4,-3)$ and the radius is $5$ , we know that

${(h=4),(k=-3),(r=5):}$

Thus, the equation of the circle is

$(x-4)^2+(y-(-3))^2=5^2$

This simplifies to be

$(x-4)^2+(y+3)^2=25$

What is the equation of the circle with a center at (4 ,-3 )(4 ,-3 ) and a radius of 5 5 ?