What is the equation of the circle with a center at $(-4 ,2 )$ and a radius of $3$ ?

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Answer 1 · 2016-01-21T18:47:11

$(x+4)^2+(y-2)^2=9$

With the center in $C(x_o,y_o)$ and radius $R$ the equation of the circle is
$(x-x_o)^2+(y-y_o)^2=R^2$

In case
$(x+4)^2+(y-2)^2=3^2$

What is the equation of the circle with a center at (-4 ,2 )(-4 ,2 ) and a radius of 3 3 ?