What is the equation of the circle with a center at $(4 ,1 )$ and a radius of $2$ ?

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What is the equation of the circle with a center at $(4 ,1 )$ and a radius of $2$ ?

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Answer 1 · 2016-01-26T09:16:25

I found: $x^2+y^2-8x-2y+13=0$

Explanation:

You can use the general equation for a circle of center at $(h,k)$ and radius $r$ as:
$(x-h)^2+(y-k)^2=r^2$
with your data:
$(x-4)^2+(y-1)^2=2^2$
$x^2-8x+16+y^2-2y+1-4=0$
$x^2+y^2-8x-2y+13=0$

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What is the equation of the circle with a center at $(4 ,1 )$ and a radius of $2$ ?

1 Answer

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