What is the equation of the circle with a center at $(-3 ,-1 )$ and a radius of $1$ ?

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Answer 1 · 2016-01-26T22:53:21

$(x+3)^2+(y+1)^2=1$

The standard form of a circle with a center at $(h,k)$ and a radius $r$ is

$(x-h)^2+(y-k)^2=r^2$

Since the center is $(-3,-1)$ and the radius is $1$ , we know that

${(h=-3),(k=-1),(r=1):}$

Thus, the equation of the circle is

$(x-(-3))^2+(y-(-1))^2=1^2$

This simplifies to be

$(x+3)^2+(y+1)^2=1$

What is the equation of the circle with a center at (-3 ,-1 )(-3 ,-1 ) and a radius of 1 1 ?