What is the equation of the circle with a center at #(-3 ,-1 )# and a radius of #1 #?

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Answer 1 · 2016-01-26T22:53:21

#(x+3)^2+(y+1)^2=1#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(-3,-1)# and the radius is #1#, we know that

#{(h=-3),(k=-1),(r=1):}#

Thus, the equation of the circle is

#(x-(-3))^2+(y-(-1))^2=1^2#

This simplifies to be

#(x+3)^2+(y+1)^2=1#