What is the equation of the circle with a center at #(2 ,6 )# and a radius of #8 #?
1 Answer
Jan 26, 2016
Explanation:
The standard form of a circle with a center at
#(x-h)^2+(y-k)^2=r^2#
Since the center is
#{(h=2),(k=6),(r=8):}#
Thus, the equation of the circle is
#(x-2)^2+(y-6)^2=8^2#
This simplifies to be
#(x-2)^2+(y-6)^2=64#