What is the equation of the circle with a center at $(2 ,6 )$ and a radius of $8$ ?

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Answer 1 · 2016-01-26T22:58:47

$(x-2)^2+(y-6)^2=64$

The standard form of a circle with a center at $(h,k)$ and a radius $r$ is

$(x-h)^2+(y-k)^2=r^2$

Since the center is $(2,6)$ and the radius is $8$ , we know that

${(h=2),(k=6),(r=8):}$

Thus, the equation of the circle is

$(x-2)^2+(y-6)^2=8^2$

This simplifies to be

$(x-2)^2+(y-6)^2=64$

What is the equation of the circle with a center at (2 ,6 )(2 ,6 ) and a radius of 8 8 ?