What is the equation of the circle with a center at #(2 ,6 )# and a radius of #8 #?

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Answer 1 · 2016-01-26T22:58:47

#(x-2)^2+(y-6)^2=64#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(2,6)# and the radius is #8#, we know that

#{(h=2),(k=6),(r=8):}#

Thus, the equation of the circle is

#(x-2)^2+(y-6)^2=8^2#

This simplifies to be

#(x-2)^2+(y-6)^2=64#