What is the equation of the circle with a center at #(2 ,-3 )# and a radius of #5 #?

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Answer 1 · 2016-01-26T22:44:32

#(x-2)^2+(y+3)^2=25#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(2,-3)# and the radius is #5#, we know that

#{(h=2),(k=-3),(r=5):}#

Thus, the equation of the circle is

#(x-2)^2+(y-(-3))^2=5^2#

This simplifies to be

#(x-2)^2+(y+3)^2=25#