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Answer 1 · 2016-01-22T21:11:58

#(x+1)^2+(y+3)^2=4#

Any general circle centred at #(a,b)# and with radius #r# has equation #(x-a)^2+(y-b)^2=r^2#.

So in this case, the equation would be

#(x+1)^2+(y+3)^2=4#