What is the equation of the circle with a center at $(- 1, 2)$ $(-1 ,2 )$ and a radius of $7$ $7$ ?

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What is the equation of the circle with a center at $(- 1, 2)$ $(-1 ,2 )$ and a radius of $7$ $7$ ?

1 Answer

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Answer 1 · 2016-02-04T01:28:33

${(x - (- 1))}^{2} + {(y - 2)}^{2} = 7^{2}$ $(x - (-1))^2 + (y- 2)^2 = 7^2$
or
${(x + 1)}^{2} + {(y - 2)}^{2} = 49$ $(x + 1)^2 + (y- 2)^2 = 49$

Explanation:

The equations of the circle is
${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x - h)^2 + (y- k)^2 = r^2$
where h is the x of the center of the circle and k is the y of the center of the circle, and r is the radius.

(-1,2) radus is 7

h = -1
k = 2
r = 7

plug in the values
${(x - (- 1))}^{2} + {(y - 2)}^{2} = 7^{2}$ $(x - (-1))^2 + (y- 2)^2 = 7^2$
simplify
${(x + 1)}^{2} + {(y - 2)}^{2} = 49$ $(x + 1)^2 + (y- 2)^2 = 49$

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What is the equation of the circle with a center at $(- 1, 2)$ $(-1 ,2 )$ and a radius of $7$ $7$ ?

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Explanation:

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