What is the derivative of $sin x + cos x$ $sinx+cosx$ ?

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What is the derivative of $sin x + cos x$ $sinx+cosx$ ?

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Answer 1 · 2018-05-29T08:23:25

$cos x - sin x$ $cosx-sinx$

Explanation:

$\frac{d}{d x} [sin x + cos x]$ $d/dx[sinx+cosx]$

Separate,

$\frac{d}{d x} [sin x] + \frac{d}{d x} [cos x]$ $d/dx[sinx]+d/dx[cosx]$

Differentiate,

$cos x - sin x$ $cosx-sinx$

Answer 2 · 2018-05-29T10:21:49

$cos x - sin x$ $cosx-sinx$

Explanation:

$using the standard derivatives$ $"using the "color(blue)"standard derivatives"$

$∙ x \frac{d}{d x} (sin x) = cos x and \frac{d}{d x} (cos x) = - sin x$ $•color(white)(x)d/dx(sinx)=cosx" and "d/dx(cosx)=-sinx$

$\frac{d}{d x} (sin x + cos x) = cos x - sin x$ $d/dx(sinx+cosx)=cosx-sinx$

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What is the derivative of $sin x + cos x$ $sinx+cosx$ ?

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Explanation:

Explanation:

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