What is the derivative of sinx - (1/3)sinx^3?

1 Answer
Jim G.
Jun 23, 2018

cosx-x^2cosx^3

Explanation:

"differentiate "sinx^3" using the "color(blue)"chain rule"

"given "y=f(g(x))" then"

dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"

d/dx(sinx^3)=cosx^3xxd/dx(x^3)=3x^2cosx^3

rArrd/dx(sinx-1/3sinx^3)

=cosx-1/3xx3x^2cosx^3

=cosx-x^2cosx^3

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