What is the derivative of $2( sinx)$ ?

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Answer 1 · 2015-06-05T23:14:20

$sinx$ has cyclic derivatives:

$f^(n)(sinx) = cosx, -sinx, -cosx, sinx, ...$
where $f^(n)(x)$ is the $n^(th)$ derivative of $f(x)$ .

$cosx$ is $f'(x)$ , $-sinx$ is $f''(x)$ , etc.

You can float out constants because they are just multipliers.

$d/(dx)[2sinx] = 2*d/(dx)[sinx] = 2cosx$

What is the derivative of 2( sinx) 2( sinx) ?