What is the average speed of an object that is still at t=0 and accelerates at a rate of a(t) = t^3-t+3 from t in [2, 3]?

1 Answer
ali ergin
Feb 15, 2016

v_a=13,75

Explanation:

v_a=int _(t1)^(t2) a(t)* d t
v_a=int _2^3 (t^3-t+3)*d t
v_a=[t^4/4-t^2/2+3t]_2^3 +C
"if t=0 then; v=O ; C=0"
v_a=[3^4/4-3^2/2+3*2]-[2^4/4-2^2/2+3*2]+0
v_a=[81/4-9/2+6]-[16/4-4/2+6]
v_a=[87/4]-[8]
v_a=55/4
v_a=13,75

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