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A car slows from 22m/s to 3m/s with a constant acceleration of –2.1m/s2. How long does this require?

1 Answer

Mar 11, 2018

$9.05 s$ $"9.05 s"$

Explanation:

$v = u + a t$ $v = u + at$

Use above equation to find time ( $t$ $t$ )

$t = \frac{v - u}{a} = \frac{3 m/s - 22 m/s}{- {2.1 m/s}^{2}} = 9.05 s$ $t = (v - u)/a = ("3 m/s "-" 22 m/s")/(-"2.1 m/s"^2) = "9.05 s"$

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