A helicopter’s speed increases from 25 m/s to 60 m/s in 5 seconds. What is the acceleration of this helicopter?

Question

41968 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-17T22:43:27

The answer is ${7 m/s}^{2}$ $"7 m/s"^2$ .

$Acceleration$ $"Acceleration"$ $= \frac{final speed - initial speed}{time}$ $= ("final speed " - " initial speed")/"time"$

So

$a = \frac{60 m/s - 25 m/s}{5 s}$ $a = ("60 m/s " - " 25 m/s") / "5 s"$

$a = \frac{35 m/s}{5 s}$ $a = "35 m/s" / "5 s"$

$a = {7 m/s}^{2}$ $a = "7 m/s"^2$

Answer 2 · 2018-04-18T00:24:27

$7 \ "m/s"^2$

We use the basic kinematics equation,

$v=u+at$

$u$ is the initial velocity of the object

$a$ is the acceleration of the object

$t$ is the time taken

Rearranging for $a$ , we get:

$a=(v-u)/t$

$v$ is the final velocity of the object

And so,

$a=(60 \ "m/s"-25 \ "m/s")/(5 \ "s")$

$=(35 \ "m/s")/(5 \ "s")$

$=7 \ "m/s"^2$