What is the average speed of an object that is still at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = t^{2} - t + 1$ $a(t) = t^2-t+1$ from $t \in [2, 3]$ $t in [2, 3]$ ?

Question

What is the average speed of an object that is still at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = t^{2} - t + 1$ $a(t) = t^2-t+1$ from $t \in [2, 3]$ $t in [2, 3]$ ?

1 Answer

Related questions

Why is acceleration measured in meters / seconds squared?
An object uniformly accelerates from 15.0m/s west to 35.0m/s west. What is the rate of...
A rocket travelling at +88m/s is accelerated to +132m/s over a 15s interval. What is its...
An object travels 8.0m south in 3.2s while uniformly accelerating at a rate of 0.71m/s2 south....
A car slows from 22m/s to 3m/s with a constant acceleration of –2.1m/s2. How long does this require?
After traveling for 6.0 seconds, a runner reaches a speed of 10 m/s. What is the runner’s acceleration?
A helicopter’s speed increases from 25 m/s to 60 m/s in 5 seconds. What is the acceleration of...
A cart rolling down an incline for 5.0 seconds has an acceleration of 4.0 m/s2. If the cart has...
How does centripetal acceleration differ from linear acceleration?
How does acceleration relate to distance?

Impact of this question

1514 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-04T11:29:32

$v_{a} = 5 - 3 = 2$ $v_a=5-3=2$

Explanation:

$\frac{d [a (t)]}{d t} = v_{a}$ $(d[a(t)])/(d t)=v_a$
$v_{a} = \int_{2}^{3} (t^{2} - t + 1) \cdot d t$ $v_a=int_2^3(t^2-t+1)*d t$
$v_{a} = {| 2 t - 1 |}_{2}^{3} + C$ $v_a=|2t-1|_2^3+C$
$if t=0 ; then C=0$
$v_a=(2*3-1)-(2*2-1)$
$v_a=5-3=2$

Science

Math

Humanities

... and beyond

What is the average speed of an object that is still at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = t^{2} - t + 1$ $a(t) = t^2-t+1$ from $t \in [2, 3]$ $t in [2, 3]$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the average speed of an object that is still at t=0t=0t=0 and accelerates at a rate of a(t) = t^2-t+1a(t)=t2−t+1a(t) = t^2-t+1 from t in [2, 3]t∈[2,3]t in [2, 3]?

1 Answer

Explanation:

Related questions

Impact of this question

What is the average speed of an object that is still at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = t^{2} - t + 1$ $a(t) = t^2-t+1$ from $t \in [2, 3]$ $t in [2, 3]$ ?