What is the average speed of an object that is not moving at t=0 and accelerates at a rate of a(t) =8-t^2/4 on t in [2,5]?

1 Answer
Jun 17, 2016

v_a=28.67" "("unit")/s

Explanation:

""we can calculate using the average value theorem"
v_a=1/(5-2)int _2^5 v(t)*d t

"v(t) represents the speed function with respect to time"

"first we must find the function v(t)"

v(t)=int a(t)*d t; " so " a(t)=8-t^2/4

v(t)=int (8-t^2/4)d t

v(t)=8t-1/4*1/3*t^3+C

"C=0 because it isn't moving at t=0"

v(t)=8t-1/12t^3+0

"now we can calculate the average speed of the object"

v_a=1/(5-2)int_2^5 (8t-1/12*t^3)d t

v_a=1/3[|8*1/2*t^2-1/12*1/4*t^4|_2^5]

v_a=1/3[|4t^2-1/48t^4|_2^5]

v_a=1/3[(4*5^2-1/48*5^4)-(4*2^2-1/48*2^4)]

v_a=1/3[(100-625/48)-(16-16/48)]

v_a=1/3[(4800-625)/48-47/48]

v_a=1/3[(4175-47)/48]

v_a=1/3[4128/48]

v_a=4128/144

v_a=28.67" "("unit")/s