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What is the average speed of an object that is moving at #2 m/s# at #t=0# and accelerates at a rate of #a(t) =t+1# on #t in [1,2]#?

1 Answer

Feb 18, 2016

#v=5/2+2=9/2 m/s#

Explanation:

#v=int _1^2 a(t)*d t#
#v=int _1^2 (t+1)d t#
#v=[1/2 t^2+t]_1^2+C#
#v=[2+2]-[1/2+1]+C#
#v=4-3/2+C#
#v=5/2+C#
#"if t=0 ; v=2; C=2"#
#v=5/2+2=9/2 m/s#

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